Program to check given year is leap year or not.

  We have been asked this question a lot of times in our childhood by our parents

  or teachers that present year is leap or not. So, now you can solve this problem

  of yours through this program coded below.

  This program will take year as an input from user and will tell you whether year

  entered by you is leap year or not in the form of output.

  Logic:-  If you divide any year by 4 and it is totally divisible and gives

  remainder 0 then it's a leap year otherwise not. 

 Program

  

   #include <stdio.h>

   #include <conio.h> 

   void main()

   {

     int n,i,m=1;

     printf("Enter any year: ");

     scanf("%d",&n);

     if(n%4==0)

      {

        printf("%d is a leap year",n);

       }

      else

       {

        printf("%d is not a leap year",n);

        }

     }

 Output:

              Output when if part is true.                                            Output when if part is False.

                         

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